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The ratio of the energy required to set ...

The ratio of the energy required to set up in a cube of side 10 cm, a uniform field of 4 `Wb//m^(2)` and a uniform electric field of `10^(6) V//m` is

A

`1.44xx10^(7)`

B

`1.44xx10^(-5)c`.

C

`1.44xx10^(6)`

D

`1.44xx10^(3)`

Text Solution

Verified by Experts

The correct Answer is:
c

`U_(E)=1/2 epsilon_(0)E^(2)xx `volume
`U_(B)=(B^(2))/(2mu_(0)) xx` volume
`:. (U_(B))/(U_(E))=(B/E)^(2) 1/(mu_(0)epsilon_(0))=(4/(10^(6)))^(2) (3xx10^(8))^(2)`
`=16/(10^(12)) xx9xx10^(16) = 144xx10^(4) =1.44xx10^(6)`
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