The maximum current that can be measured...

The maximum current that can be measured by a galvanometer of resistance `40 Omega` is 10 mA . It is converted into a voltmeter that can read upto 50 V . The resistance to be connected in series with the galvanometer is ... (in ohm )

2010

4050

5040

4960

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The correct Answer is:

To convert a galvanometer into voltmeter, the necessary value of resistance to be connected in series with the galvanometer is
`R=V/(I_(g))-G=50/(10xx10^(-3)) -40 =5000-40 =4960 Omega`

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