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A galvanometer of 100 Omega resistance g...

A galvanometer of `100 Omega` resistance gives full scale deflection when 10 mA of current is passed. To convert it into 10 A range ammeter, the resistance of the shunt required will be

A

`0.100 Omega`

B

`1.00 Omega`

C

`10.oo Omega`

D

`100.00 Omega`

Text Solution

Verified by Experts

The correct Answer is:
a
Shunt is given by
`S=(I_(g)xxR_(g))/(I-I_(g)) =(0.01xx100)/(10-0.01)=(0.01xx100)/9.99 =0.100 Omega`
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