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In a circuit 5 percent of total current ...

In a circuit 5 percent of total current passes through a galvanometer. If resistance of the galvanometer is G then value of the shunt is

A

19 G

B

`G/19`

C

20 G

D

`G/20`

Text Solution

Verified by Experts

The correct Answer is:
b
Shunt of an ammeter,
`S=(I_(g)xxG)/(I-I_(g))=(5xxG)/(100-5)=G/19`
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