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The radius of Na^(23) nucleus is...

The radius of `Na^(23)` nucleus is

A

`3.125 xx 10^(-15) m`

B

`23 xx 10^(-15) m`

C

`11 xx 10^(-15) m `

D

`1.1 xx 10^(-15) m`

Text Solution

Verified by Experts

The correct Answer is:
A
R = `R_(0)``A^(1/3)` = `1.1 xx 10 ^(-15) xx (23)^(1/3)`
= `3.125 xx 10^(-15)`m
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