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A heavy nucleus (mass number = A) splits...

A heavy nucleus (mass number = A) splits into two new nuclei, whose mass numbers are in the ratio 3:2 . The ratio of radii of these new nuclei is

A

`3:2`

B

`2:3`

C

`3^(1//3):2^(1//3)`

D

`2^(1//3) : 3^(1//3)`

Text Solution

Verified by Experts

The correct Answer is:
C

`r_(1)/r_(2) = (r_(0) xx (A_(1))^(1//3))/(r_(0) xx (A_(2))^(1//3))=(A_(1)/A_(2))^(1//3)={((3/5 xx A))/((2/5 x A))}^(1/3)=3^(1//3)/(2^(1//3)`
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