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The atomic mass of Al^(27) is 26.9815 am...

The atomic mass of `Al^(27)` is 26.9815 amu . The mass of electron is 0.0005498 amu . The rest mass energy of `Al^(27)` nucleus is

A

1862 MeV

B

25119.78 MeV

C

25113.12 MeV

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
The mass of Al nucleus is
`therefore` `m_(0)` = atomic mass - mass of total electrons
= 26.974353 amu
`therefore` E = `m_(0)`` xx ` 931 MeV
E = 26.974353 MeV
= 25113.12 MeV
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