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The atomic mass of B^(10) is 10.811 amu ...

The atomic mass of `B^(10)` is 10.811 amu . Find the binding energy of `B^(10)` nucleus . The mass of electron is 0.0005498 amu. The mass of proton is `m_(p)` = 1.007276 amu . The mass of neutron is `m_(n)` = 1.008665 amu.

A

186.54 MeV

B

678.932 MeV

C

378.932 MeV

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
The mass of `B^(10)` nucleus
`m_(0)` = 10.811 -` 5 xx 0.0005498`
10.808251 amu
Binding energy
= (5`m_(p))` + 5`m_(n)`) - mass of `B^(10)` nucleus )` xx ` 931 MeV
{(` 5 xx 1.007276 + 5 xx 1.008665) - 10.808251`}931 MeV
(10.079 - 10.808251)931MeV
- 678.932 MeV
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