Home
Class 12
PHYSICS
The binding energy per nucleon are 53 Me...

The binding energy per nucleon are 53 Mev, 6.2 MeV and 7.4 MeV for the nucleus with mass number ,3,4 and 5 respectively . If one nucleus of mass number 3 combines with one nucleus of mass number 5 to give two nuclei of mass number 4, then

A

0.3 MeV energy is absorbed

B

0.3 MeV energy is released

C

28.1 MeV energy is absorbed

D

3.3 MeV energy is absorbed

Text Solution

Verified by Experts

The correct Answer is:
D
`X^(3) + Y^(5) to 2Z^(4)`
`DeltaE=(3 xx 5.3 + 5 xx 7.4) -2(4 xx 6.2)=3.3`MeV
Promotional Banner

Topper's Solved these Questions

  • NULECUS

    BITSAT GUIDE|Exercise BITSAT Archives|8 Videos

  • MAGNETIC FIELD

    BITSAT GUIDE|Exercise All Questions|52 Videos

  • PHYSICS FOR GASEOUS STATE

    BITSAT GUIDE|Exercise BITSAT Archives|8 Videos

Similar Questions

Explore conceptually related problems

If two nuclei of mass number A_(1) and A_(2) fuse together to form a nucleus of mass number A, then

Binding energy per nucleon relation with mass number

The binding energy per nucleon of deuterium and helium nuclei are 1.1 MeV and 7.0 MeV respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is

A nucleus of mass number A has mass defect (Deltam) what is BE per nucleon of this nucleus?

If the binding energy per nucleon of deuterium is 1.115 MeV, its mass defect in atomic mass unit is

As the mass number increase binding energy per nucleon :

Write the complete symbol for (i) the nucleus with atomic number 56 and mass number 138 (ii) the nucleus with atomic number 26 and mass number 55 (iii) the nucleus with atomic number 4 and mass number 9.