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Calculate the energy of the reaction , ...

Calculate the energy of the reaction ,
`Li^(7) + p to 2 _(2)He^(4)`
If the binding energy per nucleon in `Li^(7)` and `He^(4)` nuclei are 5.60 MeV and 7.06 MeV , respectively .

A

19.6 MeV

B

2.4 MeV

C

8.4 MeV

D

17.28 MeV

Text Solution

Verified by Experts

The correct Answer is:
D
Binding energy of Li = 39.20 MeV
Binding energy of `He^(4)` = 28.24 MeV
Binding energy of `` = 56.48 MeV
`therefore` Energy = 56.48 - 39.20 = 17.28 MeV
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