A radioactive element undergoes two different types of radioactive disintegration, one with disintegration constant `lambda_(1)` and the other with `lambda_(2)`. The half-life of the element is

Options

A. `(0.693)/(lambda_(1)+lambda_(2))`
B. `(0.693)/((lambda_(1)+lambda_(2))//2)`
C. `(0.693).(lambda_(1)lambda_(2))/(lambda_(1)+lambda_(2))`
D. `(0.693lambda_(1)lambda_(2))/(2(lambda_(1)+lambda_(2)))`

Answer

A

Explanation

`lambda_(eff) =lambda_(1) + lambda_(2)`, Hence `t_(1//2) = (0.693)/(lambda_(1) + lambda_(2))`