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For measuring the activity of a radioact...

For measuring the activity of a radioactive sample, a count rate meter is used. At certain observation , count rate meter 5050 counts per minute but after 10 minute later , the count rate showed 2300 counts per minute . Calculate the disintegration constant (`lambda`)

A

0.065 per min

B

0.078 per min

C

0.24 per min

D

0.868 per min

Text Solution

Verified by Experts

The correct Answer is:
B
`dM/dt` = `lambdaN_(0)`
`therefore` `N_(0)/N = (dN_(1)//dt)/(dN_(2)//dt) = (5050)/2300) = 2.19`
Also, In `N_(0)/N=lambdat`
In (2.19) = `lambdat`
`lambda = ((2.19))/(10 = 0.078` per min
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