Home
Class 12
PHYSICS
Calculate the energy released per nucleo...

Calculate the energy released per nucleon of the reactant, in the thermonuclear reaction
`3_(1)H^(2) to _(2)He^(4)to_(2)He^(4)+_(1)H^(1)+_(0)n^(1)+21.6`MeV

A

21.6 MeV

B

7.2 MeV

C

3.6 MeV

D

1.8 MeV

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • NULECUS

    BITSAT GUIDE|Exercise BITSAT Archives|8 Videos

  • MAGNETIC FIELD

    BITSAT GUIDE|Exercise All Questions|52 Videos

  • PHYSICS FOR GASEOUS STATE

    BITSAT GUIDE|Exercise BITSAT Archives|8 Videos

Similar Questions

Explore conceptually related problems

Calculate the energy released in joules and MeV in the following nuclear reaction: ._(1)H^(2) + ._(1)H^(2) rarr ._(2)He^(3) + ._(0)n^(1) Assume that the masses of ._(1)H^(2) , ._(2)He^(3) , and neutron (n) , respectively, are 2.40, 3.0160, and 1.0087 in amu.

The nuclear reaction ._(1)^(2)H + ._(1)^(2)H to ._(2)^(4)He is called

Calculate the energy released in joules and MeV in the following nuclear reaction : ._(1)^(2) H+_(1)^(2) rarr _(2)^(3)He + _(0)^(1)n Assume that the masses of ._(1)^(2)H, _(2)^(3)He and neutron (n) respectively are 2.020, 3.0160 and 1.0087 in amu.

Calcualte the energy released (in joule and MeV ) in the follwing nulcear reaction: ._(1)^(2)H + ._(1)^(2)H rarr ._(2)^(3)He + ._(0)^(1)n Assume that the masses of ._(1)^(2)H, ._(2)^(3)He and neutron (n) are 2.0141,3.0160 and 1.0087 respectively in amu.

._(1)^(3)H and ._(2)^(4)He are:

Calculate the energy released in MeV during the reaction ._(3)^(7)Li + ._(1)^(1)H to 2[._(2)^(4)He] if the masses of ._(3)^(7)Li, ._(1)^(1)H and ._(2)H_(4)He are 7.018, 1.008 and 4.004 amu respectively.

The binding energy expressed in MeV is given for the following nuclear reactions _(2)He^(3) + _(0)n^(1) to _(2)He^(4) + 20 MeV _(2)He^(4) + _(0)n^(1) to _(2)He^(5) + 0.9 meV Which of the following conclusion is correct ?

calculate the energy released in the nuclear fusion of isotopes of hydrogen (i) ._(1)^(2)H + ._(1)^(2)H rarr ._(2)^(3)He + ._(0)^(1)n (ii) ._(1)^(2)H + ._(1)^(3)H rarr ._(2)^(4)He + ._(0)^(1)n Given that mass of neutron = 1.00867 amu {:("mass of",._(1)^(2)H = 2.01410,am u,),("mas of",._(1)^(3)H = 3.01603,am u,),("mass of ",._(2)^(3)H = 3.0160,am u,),("mass of ",._(2)^(4)He = 4.00260,am u,):}