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The stopping potential are V(1) and V(2)...

The stopping potential are `V_(1)` and `V_(2)`. Calculate the `(V_(1)-V_(2))`, if the `lambda_(1)` and `lambda_(2)` are wavelength of incident lights, respectively.

A

`(hc)/(e)((1)/(lambda_(1))-(1)/(lambda_(2)))`

B

`(hc)/(e)((1)/(lambda_(1))+(1)/(lambda_(1)))`

C

`(e)/(hc)((1)/(lambda_(1))+(1)/(lambda_(2)))`

D

`(e)/(hc)((1)/(lambda_(1))-(1)/(lambda_(2)))`

Text Solution

Verified by Experts

The correct Answer is:
A
`eV_(1)=(hc)/(lambda_(1))" and "eV_(2)=(hc)/(lambda_(2))implies(V_(1)-V_(2))=(hc)/(e)((1)/(lambda_(1))-(1)/(lambda_(2)))`
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