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Given, beta=49 and l(e)= 2ma, l(c) for a...

Given, `beta=49` and `l_(e)`= 2ma, `l_(c)` for a BJT is

A

2 mA

B

1.96 mA

C

98 mA

D

`2/49` mA

Text Solution

Verified by Experts

The correct Answer is:
B
`beta=49,l_(e)=2mA,l_(c)=?`
`beta=(l_(c)/l_(b)),alpha=(l_(c)/l_(e))`
`alpha = (beta/(1+beta)=(49)/(1+49) = (49)/(50)`
`(49)/(50) = (l_(c)/l_(e))`
`l_(c) = (49 xx 2)/(50)` mA
`l_(c) = 1.96 mA`
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