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When the plate voltage of a triode is 15...

When the plate voltage of a triode is 150 V, its cut-ff voltage is `-5V`. On increasing the plate voltate to 200V, the cut-off voltage can be

A

`-4.5`V

B

`-5.0`V

C

2.3 V

D

`-6.66 V`

Text Solution

Verified by Experts

The correct Answer is:
D
`V_(p_(1))=150V,V_(P_(2)) = 200V, V_(g_(1)) = -5V, V_(g_(2))=?`
`mu`= amplification factor of a triode valve, it is a characteristic of valve remains constant.
So long as `l_(p)` is constant.
`thereforemu=-V_(P_(1))/(V_(q_(1)))=-V_(p_(2))/V_(g_(2))`
`(150)/(-5) = (200)/(V_(g_(2)))`
`V_(g_(2)) = -20/3 = -6.66V`
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