Which of the following gates will have an output of 1 ?

Options

A.
B.
C.
D.

Explanation

To determine which of the given gates will have an output of 1, we will analyze each gate step by step using the provided inputs.

### Step-by-Step Solution:

1. **Part A: NAND Gate**
- Inputs: A = 1, B = 0
- NAND operation: The output of a NAND gate is given by the formula \( Y = \overline{A \cdot B} \).
- Calculation:
\[ Y = \overline{1 \cdot 0} = \overline{0} = 1 \]
- **Output for Part A**: 1

2. **Part B: OR Gate with NOT**
- Inputs: A = 0, B = 1
- The output of an OR gate is given by \( Y = A + B \). However, since there is a NOT gate, we have:
- Calculation:
\[ Y = \overline{A + B} = \overline{0 + 1} = \overline{1} = 0 \]
- **Output for Part B**: 0

3. **Part C: NAND Gate**
- Inputs: A = 0, B = 1
- Using the NAND formula again:
- Calculation:
\[ Y = \overline{0 \cdot 1} = \overline{0} = 1 \]
- **Output for Part C**: 1

4. **Part D: XOR Gate with NOT**
- Inputs: A = 0, B = 1
- The output of an XOR gate is given by \( Y = A \oplus B \). Since there is a NOT gate, we have:
- Calculation:
\[ Y = \overline{(A \oplus B)} = \overline{(0 \oplus 1)} = \overline{1} = 0 \]
- **Output for Part D**: 0

### Summary of Outputs:
- Part A: 1
- Part B: 0
- Part C: 1
- Part D: 0

### Final Answer:
The gates that will have an output of 1 are **Part A and Part C**.