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If lambda is the wavelength of hydrogen ...

If lambda is the wavelength of hydrogen atom from the transition `n=3 to n=1`,then what is the wavelength for doubly ionised lithium ion for same transition?

A

`lambda/3`

B

`3lambda`

C

`lambda/9`

D

`9lambda`

Text Solution

Verified by Experts

The correct Answer is:
C
For wavelength ,`1/lambda=RZ^(2)((1)/n_(1)^(2)-(1)/n_(2)^(2)) `
Here,transition is same
So,`lambdapropto 1/Z^(2) `
`lambda_(H)/lambda_(Li)=(Z_(LI))^(2)/(Z_(H))^(2)=(3)^(1)/(1)^(2)=9`
Rightarrow` lambda_(Li)=lambda_(H)/9=lambda/9`
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