In accordance to Arrhenius equation, the plot of log k against `(1)/(T)` is a straight line. The slope of the line is equal to

Options

A. `(-E_(a))/(R )`
B. `(-2.303)/(E_(a).R)`
C. `(-E_(a))/(2.303R)`
D. `(-E_(a))/(2.303)`

Answer

C

Explanation

Arrhenius equation can be written as
`logk=logA-(E_(a))/(2.303R)`,
On comparing this equation with the straight line equation,
`y=mx+c`
we get,, `y=logk, m=-(E_(a))/(2.303R),x=(1)/(T),C=logA`