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For the first order reaction, k=5.48 xx ...

For the first order reaction, `k=5.48 xx 10^(-4)s^(-1)`, the two-third life time for this reaction is

A

2005 s

B

1000 s

C

2000 s

D

3005 s

Text Solution

Verified by Experts

The correct Answer is:
A
For first order reaction, we know that
`k=(2.303)/(t).log.(a)/((a-x))`
Hence, `t=(2.303)/(5.48 xx 10^(-4))xxlog .(a)/(a-(2)/(3)a)`
`=(2.303xx10^(4))/(5.48)xxlog3`
`=(2.303xx10^(4))/(5.48)xx0.4771=2005s`
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