The rate constant for the first order reaction is `60 s^(-1)`. How much time will it take to reduce the concentration of the reactant to `1//16th` value ?

Options

A. `4.6 xx 10^(4) s`
B. `4.6 xx 10^(-4) s`
C. `4.6 xx 10^(-2) s`
D. `4.6 xx 10^(2) s`

Answer

C

Explanation

For the first order reaction, `k=(2.303)/(t)log.([A_(0)])/([A])`
Then, `k=(2.303)/(t)log. ((a)/(a//16))=0.0462=4.62xx10^(-2)s`