The half-time of the following first order decomposition of nitramide is 2.1 h at `15^(@)C`:
`NH_(2)NO_(2)(aq)rarrN_(2)O(g)+H_(2)O(l)`
If 6.2 g of nitramide is allowed to decompose then time taken for it to decompose 99%, will be

Options

A. 2.1 h
B. 12 h
C. 13.96 h
D. 33 h

Answer

C

Explanation

For the first order reaction,
`k=(0.693)/(t_(1//2))=(0.693)/(2.1)=0.33 h^(-1)`
and `k=(2.303)/(t)log_(10).(a)/((a-x))`
or `t=(2.303)/(k)log_(10).(100)/((100-99))`
`=(2.303)/(0.33)xx2=13.96h`