Consider the following reaction
`2N_(2)O_(5)iff 4NO_(2)+O_(2)`.
If rate and rate constant for above reaction are `2.40 xx 10^(-5)` mol `L^(-1) s^(-1)` and `3 xx 10^(-5) s^(-1)` respectively, then calculate the concentration of `N_(2)O_(5)`.

Options

A. 1.4 mol `L^(-1)`
B. 1.2 mol `L^(-1)`
C. 0.04 mol `L^(-1)`
D. 0.8 mol `L^(-1)`

Answer

D

Explanation

For a first order reaction, Rate, `k[N_(2)O_(5)]`
`2.4 xx 10^(-5)=3xx10^(-5)xx[N_(2)O_(5)]`
`[N_(2)O_(5)]=(2.4xx10^(-5))/(3xx10^(-5))=0.8 " mol "L^(-1)`