If the normal at the end of latus rectum of the ellipse `x^2/a^2+y^2/b^2=1` passes through (0, b) then `e^4+e^2` (where e is eccentricity) equals

If the normal at an end of latus rectum of the hyperbola x^(2)/a^(2) - y^(2)/b^(2) = 1 passes through the point (0, 2b) then

If the normal at an end of latus rectum of the hyperbola x^(2)/a^(2) - y^(2)/b^(2) = 1 passes through the point (0, 2b) then

The normal at an end of a latus rectum of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 passes through an end of the minor axis if

The normal at an end of a latus rectum of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 passes through an end of the minor axis if

If the normal at one end of a latus rectum of the ellipse x^2/a^2+y^2/b^2=1 passes through one end of the minor axis, then show that e^4+e^2=1 [ e is the eccentricity of the ellipse]

If the normal at the end of latus rectum of an ellipse x^(2)//a^(2)+y^(2)//b^(2)=1 of eccentricity e passes through one end of the minor axis then e^(4)+e^(2)=

If the normal at one end of the latus rectum of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 passes through one end of the minor axis, then prove that eccentricity is constant.

If the normal at one end of the latus rectum of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 passes through one end of the monor axis, then prove that eccentricity is constant.