The number of halides that do not exist among the following:
`CuF_(2),CuCl_(2),CuBr_(2),CuI_(2),CuCl,CuBr,Cu_(2)I_(2),CuF`

Explanation

To determine the number of halides that do not exist among the given copper halides, we will analyze each compound based on the oxidation states of copper and the stability of the halides.

### Step-by-Step Solution:

1. **Identify the Oxidation States of Copper**:
- Copper can exist in two oxidation states: +1 and +2.

2. **List the Given Halides**:
- The halides provided are:
- CuF₂
- CuCl₂
- CuBr₂
- CuI₂
- CuCl
- CuBr
- Cu₂I₂
- CuF

3. **Analyze Each Halide**:
- **CuF₂**: Copper in +2 oxidation state. This compound exists.
- **CuCl₂**: Copper in +2 oxidation state. This compound exists.
- **CuBr₂**: Copper in +2 oxidation state. This compound exists.
- **CuI₂**: Copper in +2 oxidation state. However, CuI₂ does not exist because iodide ions are strong reducing agents and will reduce CuI₂ to CuI.
- **CuCl**: Copper in +1 oxidation state. This compound exists.
- **CuBr**: Copper in +1 oxidation state. This compound exists.
- **Cu₂I₂**: This can be viewed as 2CuI, which exists since copper can form bonds with iodide in the +1 state.
- **CuF**: Copper in +1 oxidation state. However, CuF does not exist because fluorine is highly electronegative and does not favorably bond with copper.

4. **Count the Non-Existent Halides**:
- The halides that do not exist are:
- CuI₂
- CuF
- Therefore, there are **2 halides that do not exist**.

### Final Answer:
The number of halides that do not exist is **2** (CuI₂ and CuF).