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Select the correct statement(s) about ch...

Select the correct statement(s) about chemical behavior of lanthanoids:

A

`II^(nd)` I.E. are comparable with those of calcium.

B

Earlier members of the series are quite reactive, similar of calcium.

C

With increasing atomic number, they behave more like aluminium.

D

The metals combine with hydrogen when gently heated in the gas.

Text Solution

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The correct Answer is:
To solve the question regarding the chemical behavior of lanthanides, we will analyze each statement provided and determine their correctness based on the known properties of lanthanides. ### Step-by-Step Solution: 1. **Understanding the Electronic Configuration**: - First, we need to know the electronic configuration of calcium (Ca) and a representative lanthanide, cerium (Ce). - Calcium: \( \text{[Ne]} 3s^2 \) (or \( 1s^2, 2s^2, 2p^6, 3s^2 \)) - Cerium: \( \text{[Xe]} 4f^1 5d^1 6s^2 \) 2. **Analyzing the First Statement**: - The first statement claims that the second ionization energy of lanthanides is equal to that of calcium. - The second ionization energy of calcium is approximately 1100 kJ/mol. For cerium, it is also around the same value, indicating that this statement is **correct**. 3. **Analyzing the Second Statement**: - The second statement suggests that early members of lanthanides are quite reactive, similar to calcium. - Since both calcium and cerium have two electrons in their outermost s-orbital (4s for Ca and 6s for Ce), they exhibit similar reactivity. Thus, this statement is also **correct**. 4. **Analyzing the Third Statement**: - The third statement posits that as the atomic number increases, lanthanides start behaving like aluminum. - Aluminum is in the p-block, and as we move across the lanthanides, they do exhibit some behavior similar to p-block elements due to the filling of f-orbitals. Therefore, this statement is also **correct**. 5. **Analyzing the Fourth Statement**: - The fourth statement states that when lanthanides combine with hydrogen, they form hydrides gently. - Lanthanides do react with hydrogen to form hydrides, and this reaction is typically mild. Hence, this statement is also **correct**. ### Conclusion: After analyzing all statements, we conclude that **all statements regarding the chemical behavior of lanthanides are correct**. ### Final Answer: All statements about the chemical behavior of lanthanides are correct. ---

To solve the question regarding the chemical behavior of lanthanides, we will analyze each statement provided and determine their correctness based on the known properties of lanthanides. ### Step-by-Step Solution: 1. **Understanding the Electronic Configuration**: - First, we need to know the electronic configuration of calcium (Ca) and a representative lanthanide, cerium (Ce). - Calcium: \( \text{[Ne]} 3s^2 \) (or \( 1s^2, 2s^2, 2p^6, 3s^2 \)) - Cerium: \( \text{[Xe]} 4f^1 5d^1 6s^2 \) ...
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