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Half life period of ""(53)I""^(125) is 6...

Half life period of `""_(53)I""^(125)` is 60 days. Percentage of radioactivity preent after 180 days is

A

0.5

B

0.75

C

0.36

D

0.125

Text Solution

Verified by Experts

The correct Answer is:
d
`N=N""_(0)/2""^(n)(n=180/60=3)`
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