`^^_(m_((NH_(4)OH)))^(o)` is equal to

Options

A. `^^_(m)^(o)(NH_(4)OH)+^^_(m)^(o)(NH_(4)Cl)-^^ ^(o)(HCI)`
B. `^^_(m)^(o)(NaOH)+^^_(m)^(o)(NH_(4)Cl)-^^ ^(o)(NaCl)`
C. `^^_(m)^(o)(NH_(4)Cl)+^^_(m)^(o)(NaCl)-^^ ^(o)(NaOH)`
D. `^^_(m)^(o)(NaOH)+^^_(m)^(o)(NaCl)-^^ ^(o)(NH_(4)Cl)`

Answer

B

Explanation

This question is based on the concept of Kohlrausch law and can be solved by using the concept involved in calculation of limiting molar conductivity of any salt According to Kohlraush law limiting molar conductivity of any salt is equal to sum of individual molar conductivities of cations and anions of electroyte.
`{:(^^_(m(NH_(4)Cl))^(o)=^^_(m(NH_(4)^(+)))^(o)-^^_(m(Cl^(-)))^(o)),(^^_(m(NaOH))^(o)=^^_(m(Na^(+)))^(o)-^^_(m(OH^(-)))^(o)),(^^_(m(NaCl))^(o)=^^_(m(Na^(+)))^(o)+^^_(m(Cl^(-)))^(o)),(" - - -"),(bar(^^_(m(NH_(4)Cl))^(o)+^^_(m(NaOH))^(o)-^^_(m(NaCl))^(o))=^^_(m(NH_(4)OH))^(o)):}`
Hence, option (b) is corrent choice.