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For the half cell At pH = 3 electro...

For the half cell

At pH = 3 electrode potential is

A

`1.36 V`

B

`1.30 V`

C

`1.42 V`

D

`1.20 V`

Text Solution

Verified by Experts

The correct Answer is:
B
[A] = [B] in quinhydrane electrode
`E=E^(@)-(0.0591)/(2)log [H^(+)]^(2)`
`=E^(@)+0.059 1P^(H)=1.42V`
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