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For the galvanic cell : Ag|AgCl(s)),KC...

For the galvanic cell `:`
`Ag|AgCl(s)),KCl(0.2M)||KBr(0.001M),AgBr(s)|Ag,` calculate the `EMF` generated and assign correct polarity to each electrode for a spontaneous process after taking into account the cell reaction at `25^(@)C`.
`[K_(sp)(AgCl)=2.8xx10^(-10),K_(sp)(AgBr)=3.3xx10^(-13)]`

A

`0.057 V`

B

`0.021 V`

C

`-0.052 V`

D

`-0.037 V`

Text Solution

Verified by Experts

The correct Answer is:
D
`[Ag^(+)]` in L.H.E = `(2.8xx10^(-10))/(0.2)=1.4xx10^(-9)m`
`[Ag^(+)]` in R.H.E = `(3.3xx10^(-13))/(10^9-3)=3.3xx10^(-13)m`
`E_("cell")=(E_(C )^(@)-E_(A)^(@))-(0.059)/(1)."log"(1.4xx10^9-9)/(3.3xx10^(-13)`
`=-0.0377`
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