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During the working of the following cell...

During the working of the following cell
`Pb-Hg(1M)|Pb^(2+)(aq)(0.1M)|`
`|Pb^(2+)(aq)(0.1M)|Pb-Hg(0.5M)`

A

`[Pb^(2+)]` decreases in cathodic half cell

B

`[Pb^(2+)]` increases in anodic half cell

C

`[Pb^(2+)]` increases in cathodic half cell

D

Conc. Of lead amalgam increases in cathodic half cell whereas decreases in anodic half-cell

Text Solution

Verified by Experts

The correct Answer is:
A
During the working of cell, Pb is oxidized at anode and `Pb^(+2)` is reduced at cathode.
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