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A fuell cell uses CH(4)(g) and forms CO(...

A fuell cell uses `CH_(4)(g)` and forms `CO_(3)^(2-)` at the anode. It is used to power a car with 80 amp, for 0.96 hr. how many litres of `CH_(4)(g)` (at 1 atm, 273 K) would be required? (V_(m) = 22.4 L/mol) (F = 96500). Assume `100%` efficiency.

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The correct Answer is:
8
`CH_(4)+10OH^(-)rarr CO_(3)^(2-)+7H_(2)O+8e`
no of moles `=(q)/(ZF)`
`=(80xx0.96xx3600)/(8xx96500)=0.358`
`V_(CH_(4)` (lit) at STP
required `=0.358xx22.4=8.02` lit
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