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IUPAC name of Li[AIH(4)] is...

IUPAC name of `Li[AIH_(4)]` is

A

Lithium aluminium hydride

B

Lithium tetrahydrido aluminate (III)

C

Tetrahydride aluminium lithionate

D

Aluminium lithium hydride

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The correct Answer is:
To find the IUPAC name of the compound `Li[AlH₄]`, we can follow these steps: ### Step 1: Identify the components of the compound The compound consists of lithium (Li) and a coordination complex `[AlH₄]`. In the complex, aluminum (Al) is the central metal atom, and there are four hydride (H⁻) ligands surrounding it. ### Step 2: Name the cation The cation in this compound is lithium. In IUPAC nomenclature, we simply write "lithium". ### Step 3: Identify and name the ligands The ligands in the coordination complex are hydride ions (H⁻). Since there are four hydride ligands, we use the prefix "tetra-" to indicate the number. The name of the hydride ligand in coordination chemistry is "hydrido". Therefore, we write "tetrahydrido" for the four hydride ligands. ### Step 4: Name the central metal The central metal in the complex is aluminum (Al). In coordination compounds, if the metal is in a positive oxidation state, we simply use its name. However, since the overall charge of the complex is negative, we need to modify the name of aluminum to reflect this. The correct modification is to use "aluminate" for aluminum in a negatively charged complex. ### Step 5: Determine the oxidation state of the metal To find the oxidation state of aluminum in this complex, we consider the charges: - Lithium has a +1 charge. - Each hydride has a -1 charge, and there are four of them, contributing a total of -4 charge. To balance the charges: - Let the oxidation state of aluminum be \( x \). - The total charge of the complex is \( +1 + x - 4 = 0 \). - Solving for \( x \) gives us \( x = +3 \). ### Step 6: Combine the names Now we can combine the names we have found: - Cation: lithium - Ligands: tetrahydrido - Anion: aluminate (with the oxidation state indicated as 3) Putting it all together, the IUPAC name of the compound `Li[AlH₄]` is: **Lithium tetrahydridoaluminate(III)**. ### Final Answer: **Lithium tetrahydridoaluminate(III)** ---

To find the IUPAC name of the compound `Li[AlH₄]`, we can follow these steps: ### Step 1: Identify the components of the compound The compound consists of lithium (Li) and a coordination complex `[AlH₄]`. In the complex, aluminum (Al) is the central metal atom, and there are four hydride (H⁻) ligands surrounding it. ### Step 2: Name the cation The cation in this compound is lithium. In IUPAC nomenclature, we simply write "lithium". ...
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NARAYNA-COORDINATION COMPLEXES-LEVEL-I (H.W)
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  6. Chelates are used in

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  7. Hexaaquatitanium (III) chloride is

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  8. IUPAC name of Li[AIH(4)] is

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  9. Dipole moment will be zero in the complexes

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  10. The number of geometrical isomers of [Co(NH(3))(3)(NO(3))(3)] is

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  11. For the given complex [CoCl(2)(en)(N(3))(2)]^(+), the number of geomet...

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  12. Which does not obey EAN rule?

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  13. The following solutions requires three moles of AgNO(3) for the comple...

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  14. AgCl dissolved in excess of NH(3), KCN and Na(2)S(2)O(3) solutions the...

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  15. The secondary valency of chromium in [Cr(en)(3)]Cl(3) is

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  17. If Delta(0) gt P, the correct electronic configuration for d^(4) syste...

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  18. The ligand that gives dark blue color with curic ion in the laboratory...

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