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On treatment of [Pt(NH(3))(4)]^(2+ with ...

On treatment of `[Pt(NH_(3))_(4)]^(2+` with Cl compound I is formed When `[PtCl_(4)]^(2-)` reacted with aq. `NH_(3)` the complex II is formed. Point out the correct statement.

A

I cis. II trans, both tetrahedral

B

I cis, II trans, both square planar

C

I trans, II cis, both tetrahedral

D

I trans, II cis, both square planar

Text Solution

Verified by Experts

(D), I trans- `[Pt(NH_(3))_(2)]Cl_(2)`
II: cis - `[Pt(NH_(3))_(2)Cl]` trans effect.
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