Home
Class 12
CHEMISTRY
K(2)Cr(2)O(7) is preferred oxidizing ag...

`K_(2)Cr_(2)O_(7)` is preferred oxidizing agent than `Na_(2)Cr_(2)O_(7)` because

A

`Na_(2)Cr_(2)O_(7)` is hygroscopic

B

`K_(2)Cr_(2)O_(7)` is hygroscopic

C

`Na_(2)Cr_(2)O_(7)` is not an oxidizing agent

D

`K_(2)Cr_(2)O_(7)` is oxidizing and hygroscopic

Text Solution

Verified by Experts

The correct Answer is:
A
Due to `Na_(2)Cr_(2)O_(7)` is hygroscopic
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY OF HEAVY METALS

    NARAYNA|Exercise SINGle Answer Questions(LEVEL-II)|36 Videos

  • CHEMISTRY OF HEAVY METALS

    NARAYNA|Exercise Level III Single Answer Questions|13 Videos

  • CHEMISTRY IN EVERYDAY LIFE

    NARAYNA|Exercise ASSERTION & REASON TYPE QUESTIONS|10 Videos

  • CO-ORDINATE COMPOUNDS

    NARAYNA|Exercise Exercise-4|60 Videos

Similar Questions

Explore conceptually related problems

K_(2)Cr_(2)O_(7) is preferred to Na_(2)Cr_(2)O_(7) for use in volumetric analysis as a primary standard because

In laboratory K_(2)Cr_(2)O_(7) is used mainly not Na_(2)Cr_(2)O_(7). Why?

K_(2)Cr_(2)O_(7) , on heating gives

The oxidation state of Cr in K_(2)Cr_(2)O_(7) is: