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When Cu powder is heated with CuCl(2) so...

When Cu powder is heated with `CuCl_(2)` solution, the compound obtained is

A

`Cu[CuCl_(4)]`

B

`Cu_(2)[CuCl_(4)]`

C

`Cu_(2)O`

D

`Cu_(2)Cl_(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Cu reduces `CuCl_(2)` to `Cu_(2)Cl_(2)`
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