The empirical formula of a compound is `CH_(2)O` and its molecular mass is 120. The molecular formula of the comound is

Options

A. `C_(2)H_(4)O_(2)`
B. `C_(3)H_(6)O_(3)`
C. `C_(4)H_(8)O_(4)`
D. `CH_(2)O`

Answer

C

Explanation

Empirical formula weight of the compound
`12+2+16=30`
`n=("mol.wt.")/("Emp.formulawt.")=120/30=4`
`:.` molecular formula of the compound is `(CH_(2)O)_(4)=C_(4)H_(8)O_(4)`