`HCOOH` and `CH_(3)COOH` can be distinguished by

Options

A. Tollen's reagent
B. Fehling's solution
C. `KKnO_(4)`
D. `NaHCO_(3)`

Answer

A, B, C, D

Explanation

(a) `HCOOH` gives silver mirror with Tollen's reagent, acetic acid does not.
(b) `HCOOH` forms red ppt with Fehling's solution, acetic does not
(c) `HCOOH` decolourises `KMnO_(4)` but acetic acid does not.
(d) Both react with `NaHCO_(3)` since (d) is not correct.