In the cyclic process shown in the `V-P` diagram the magnitude of the work is done is
A
`pi((P_(2)-P_(1))/(2))^(2)`
B
`pi ((V_(2)-V_(1))/(2))^(2)`
C
`(pi)/(4) (P_(2)-P_(1))(V_(2)-V_(1))`
D
`pi(V_(2)-V_(1))^(2)`
Text Solution
Verified by Experts
The correct Answer is:
C
Process direction in V-P diagram is clockwise so process direction in P-V diagram is anti-clockwise. Net work done by system = Area `=pixx((P_(2)-P_(1)))/(2).((V_(2)-V_(1)))/(2)`
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