Home
Class 12
CHEMISTRY
The rate law for the reaction RCl+Na(aq....

The rate law for the reaction `RCl+Na(aq.)rarrROH+NaCl` is given by, rate `=K_(1)[RCl].` The rate of the reaction will be :

A

doubled on doubling the concentration of sodium hydroxide

B

halved on reducing the concentration of alkyl halide to half

C

decreased on increasing the temperature of the reaction

D

unaffected by inceasing the temperature of the reaction

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • HALIDES

    HIMANSHU PANDEY|Exercise Level 1 (Q.26 To Q.48)|23 Videos

  • HALIDES

    HIMANSHU PANDEY|Exercise Level 2 (Q.1 To Q.25)|25 Videos

  • GENERAL ORGANIC CHEMISTRY

    HIMANSHU PANDEY|Exercise Subjective Type Problems|19 Videos

  • ISOMERISM

    HIMANSHU PANDEY|Exercise Subjective Type Problems|11 Videos

Similar Questions

Explore conceptually related problems

The rate law for the reaction, RCl + Na (a) rarr ROH + NaCl is given by, rate = K_(1) [RCl]. The rate of the reaction will be -

The rate law for the reaction RCl + NaOH(aq) rarr ROH + NaCl is given by Rate = k[RCl] . The rate of the reaction will be

The rate law for the reaction RCl + NaOH(aq) to ROH + NaCl is given by Rate =K_1[RCl] . The rate of the reaction will be

The rate for the reaction: RCl+NaOH(aq)rarr ROH+NaCl is given by rate = k_(1)[RCl] The rate of the reaction is: (A) Doubled on doubling the concentration of "NaOH (B) Halved on reducing the concentration of "RCl" to half (C) Decreased on increasing the temperature of reaction (D) Unaffected by increasing the temperature of the reaction

The rate law for the reaction RCl+NaOH (aq) to ROH +NaCl is given by rate k_(1)[RCl] the rate of reaction will be doubled on doubling the concentration of NaOH.

The differential rate law for the reaction