Differentiate `sin^(-1)(3x-4x^3)`

Explanation

To differentiate the function \( y = \sin^{-1}(3x - 4x^3) \), we will follow these steps:

### Step 1: Differentiate using the chain rule
The derivative of \( y = \sin^{-1}(u) \) where \( u = 3x - 4x^3 \) is given by:
\[ \frac{dy}{dx} = \frac{1}{\sqrt{1 - u^2}} \cdot \frac{du}{dx} \]

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