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The gas obtained by roasting of sulphide...

The gas obtained by roasting of sulphide ore is reacted with acidified potassium dichromate. A green colored compound 'X' is formed. The compound X can be :

A

`SO_(2)`

B

`Cr_(2)(SO_4)_(3)`

C

`Cl_(2)`

D

`CrO_(2)Cl_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to identify the gas produced by roasting a sulphide ore and its reaction with acidified potassium dichromate, which leads to the formation of a green-colored compound 'X'. ### Step 1: Identify the gas produced by roasting sulphide ore - Roasting is a process where a sulphide ore is heated in the presence of oxygen. - For example, if we take lead(II) sulphide (PbS) or zinc sulphide (ZnS), they react with oxygen to form their respective oxides and release sulfur dioxide (SO2) gas. **Hint:** Remember that roasting involves heating sulphide ores in the presence of oxygen, leading to the formation of oxides and the release of SO2 gas. ### Step 2: Reaction of SO2 with acidified potassium dichromate - The next step is to consider the reaction of sulfur dioxide (SO2) with acidified potassium dichromate (K2Cr2O7). - Acidified potassium dichromate is a strong oxidizing agent. In acidic conditions, SO2 can be oxidized to sulfuric acid (H2SO4). **Hint:** Acidified potassium dichromate is used as an oxidizing agent; think about how it reacts with reducing agents like SO2. ### Step 3: Formation of the green-colored compound - The reaction can be summarized as follows: \[ SO_2 + K_2Cr_2O_7 + H_2SO_4 \rightarrow K_2SO_4 + Cr_2(SO_4)_3 + H_2O \] - The chromium in potassium dichromate (Cr^6+) is reduced to Cr^3+, which is responsible for the green color of the compound formed, specifically chromium(III) sulfate (Cr2(SO4)3). **Hint:** The color change from orange (due to Cr^6+) to green (due to Cr^3+) is a key indicator of the reaction taking place. ### Conclusion - The green-colored compound 'X' formed in this reaction is chromium(III) sulfate (Cr2(SO4)3). **Final Answer:** The compound X can be chromium(III) sulfate (Cr2(SO4)3). ### Summary of Steps: 1. Identify the gas produced by roasting sulphide ore (SO2). 2. Understand the reaction of SO2 with acidified potassium dichromate. 3. Recognize the formation of the green-colored compound (Cr2(SO4)3).
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