Two uniform thin identical rods AB and CD each of mass M and length L are joined so as to form a cross as shown. The moment of inertia of the cross about a bisector line EF is :-

Options

A. `(ML^2)/6`
B. `(ML^2)/4`
C. `(ML^2)/12`
D. `(ML^2)/3`

Answer

C

Explanation

Break the rod in two parts each of mass M/2 and length L/2
`4xx(M/2(L/(2sqrt2))^2)/3`