Following figure shows a network of eight resistors, each equal to `2 Omega` , connected to a 3 V battery of negligible internal resistance. The current I in the circuit is :-

Options

A. 0.25 A
B. 0.50 A
C. 0.75 A
D. 1.0 A

Answer

D

Explanation

Because of symmetry , BE and CF are ineffective
`therefore ` AB,BC and CD are in series . Total resistance
`R_1=6Omega`
AE,EF and FD are in series . Total resistance
`R_2=6Omega`
When they are is parallel , total resistance = `3Omega`
`therefore ` Current =` (3V)/(3Omega)`=1.0 A