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A proton and alpha particle, after accel...

A proton and `alpha` particle, after accelerating through same potential difference enters into a uniform magnetic field perpendicular to their velocities, find the radius ratio of proton and `alpha` particle:-

A

`1:2`

B

`1:1`

C

`2:1`

D

`1:sqrt2`

Text Solution

Verified by Experts

The correct Answer is:
A
`r=sqrt(2qvm)/(Bq)` or `rprop sqrt(m/q)`
`r_p/r_alpha =sqrt(m_p/m_alpha)sqrt(q_n / q_p) = sqrt(1/4)sqrt(2/1)=1/sqrt2`
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