Two protons are placed 1 Å apart. If they are released, what will be the kinetic energy of each proton when they are at large separation :-

Options

A. `2.56 xx 10^(–19) J `
B. `11.52 xx 10^(-19)` J
C. `23.04 xx 10^(-19)` J
D. `2.56 xx 10^(-28) J`

Answer

B

Explanation

Potential energy = KE at large separation
`(1)/(2) xx ((e ) (e ) )/( 4 pi epsi _(0) r) = (KE "at large separation ")/( 2)`
`=KE ` of each proton
KE of each proton
` =(1)/(2) xx (9 xx 10 ^(9) xx (1.6 xx 10 ^(-19 ))^(2))/( 10 ^(-10))`
`= 11.52 xx 10 -19 J.`