The function `f(x)={x^2a a`,if1lt=x

Explanation

To find the most suitable values of \( a \) and \( b \) such that the function

\[
f(x) =
\begin{cases}
\frac{x^2}{a} & \text{if } 0 < x < 1 \\
a & \text{if } 1 \leq x < \sqrt{2} \\
\frac{2b^2 - 4b}{x^2} & \text{if } \sqrt{2} \leq x < \infty
...