If `f(x)={(x-4)/(|x-4|a+b ,ifx=4)+a ,ifx<4(x-4)/(|x-4|)+b ,ifx >4i scon t inuou sa tx=4,fin da , b`

Answer

`a=1`

`b= -1`

Explanation

`f(4^{-})=f(4^{+}) &=f(4)`


`\frac{x-4}{(x-4)} + a = \frac{x-4}{(x-4)}+b = a+b`


`a-1 = b+1 `

` b+1 = a+b` (ii)

`a=1`

`b= -1`