The value of `b` for which the function `f(x)={5x-4,0xlt=1`
, `4x^2+3b x ,1< x <2`
and continuous at `x=1`

Answer

`therefore b = - 1`

Explanation

ATQ,


f(x)=\begin{cases}5 x-4 , 0 < x \le 1 \\ 4 x^{2}+3 b x , 1 < x < 2
\end{cases}

` f(x)` is continuous.



`implies` LHL = RHL `= f(x)`



`implies \lim _{x \rightarrow 1} \quad 5 x-4=\lim _{x \rightarrow 1} \quad 4 x^{2}+3 b x=1`


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