Find the values of `aa n db` so that the function `f(x)` defined by `f(x)={x^2+a x+b,0lt=x<2 3x+2,2lt=xlt=42a x+5b ,4

Answer

`:. a=3, b=-2 `

Explanation

\begin{aligned}
&f\left(2^{-}\right)=f\left(2^{+}\right)=f(2) \\
&4+2 a+b=8 \\
&2 a+b=4, &\text { (i) } \\ \\
&f\left(4^{+}\right)=f(4) \\
&f(4)=14, \\
&\left(8a+5b)=\right(14), &\text {(ii)} \\ \\
\text { Now, } \
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